数字转中文

# coding: utf-8
"""\
规则:
1. 中文分为数字（零、一、二、三、四、伍、六、七、八、九），数位[个、十、百、千、万、亿]和符号[负，点]三部分
2. 数位个略去
3. 以一十开头略去首位一
4. 数位为零，保留数字零略去该数位单位
5. 连续数位为零，保留一个零
6. 个，万，亿位为零，略去零
7.
"""
numbers = ["零", "一", "二", "三", "四", "五", "六", "七", "八", "九"]
units = ["亿", "万", "千", "百", "十", ""]
def i2c(i, recursive=False):
    if i < 0:
        return '负'+i2c(abs(i))
    if i == 0:
        return "零"
    elif i < pow(10, 4):
        result = ""
        for d, u in zip(str(i).zfill(4), units[2:]):
            result += numbers[int(d)]+u if d != "0" else "零"
    elif i < pow(10, 8):
        wj, rest = divmod(i, pow(10, 4))
        result = i2c(wj)+"万"+("零" if rest < pow(10, 3) else "")+i2c(rest, True)
    else:
        yi, rest = divmod(i, pow(10, 8))
        result = i2c(yi)+"亿"+("零" if rest < pow(10, 7) else "")+i2c(rest, True)
    result = "零".join(result.replace("零", " ").split())
    return result[1:] if result.startswith('一十') and not recursive else result
def f2c(f):
    if f == '':
        f = '0'
    return '点'+''.join(map(lambda d: numbers[int(d)], f))
def n2c(n):
    nsplit = n.split('.')
    i = int(nsplit[0]) if nsplit[0] else 0
    if len(nsplit) == 1:
        return i2c(i)
    elif len(nsplit) == 2 and n != '.':
        return i2c(i)+f2c(nsplit[1])
    else:
        raise ValueError
if __name__ == '__main__':
    import sys
    print(n2c(sys.argv[1]))